What is #(4sqrt81) / 3 + (5 root3 8)/2#?

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Answer 1 · 2015-12-02T03:00:07

#=color(blue)(17#

#(4sqrt(81))/3 +(5root(3)8)/2#

We know that
#sqrt81=color(blue)(9#

#root(3)8 = 8^(1/3) = 2^(3*(1/3)) = color(blue)(2#

So the expression becomes:
#(4sqrt(81))/3 +(5root(3)8)/2 = (4*color(blue)(9))/3 + (5*color(blue)(2))/2#

#=36/3+10/2#

The L.C.M of the expression is #6#

#=(36*2)/(3*2)+(10*3)/(2*3)#

#=(72)/(6)+(30)/(6)#

#=(cancel102)/(cancel6)#

#=color(blue)(17#