First, we find the slope #m# of the line.
The slope of the line is the change in #y# per unit of change in #x#. Equivalently, this means that a line with slope #a/b# will rise #a# units as #x# increases by #b# units. Then, we can find the slope from two points with the following formula:
#m = ("change in "y)/("change in "x) = (y_2-y_1)/(x_2-x_1)#
In this case, that gives us
#m = (6-14)/(19 - (-17)) = -8/36 = -2/9#
Now, we can write the equation using the point-slope form of a line.
#y - y_1 = m(x - x_1)#
Picking either of the points will work, so let's use #(19, 6)# (as an exercise, verify that this gives the same result if you use the other point). This gives us the equation
#y - 6 = -2/9(x - 19)#
If we wish to put that into the more common slope-intercept form, we can just multiply it out and solve for #y#.
#y - 6 = -2/9x + 38/9#
# y = -2/9x + 92/2#