How do you solve #x - 2y = -2# and #y = 2x + 4# by substitution?

1 Answer
Eswer S.
Dec 5, 2015

#x=-2# and #y=0#

Explanation:

#x-2y=-2#

This implies #x=2y-2#

Substitute this value of x in the other equation i.e #y=2x+4#
#y=2(2y-2)+4#
#y=4y#
This implies #y=0#

Substitute this in the first equation
#x-2(0)=-2#
This implies #x=-2#

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