Question

What are the mean and standard deviation of a binomial probability distribution with `n=9` and `p=11/32`?

Answer 1

mean `=np`

s.d. `=sqrt(npq)`

Explanation:

Using the formula for mean and s.d. above ...

mean `=9xx11/32=99/32~~3.09`

s.d. `=sqrt(9xx11/32xx(1-11/32))~~1.425`

hope that helped