Question

When sprinting, Rich can accelerate at `0.5` `m``/``s^2`. How many seconds would it take Rich to sprint a distance of 200 m if he starts from rest?

Answer 1

`28.28"s"`

Explanation:

Use:

`s=ut+1/2at^2`

Since `u=0` then

`s=1/2at^2`

`:.t=sqrt((2s)/a)=sqrt((2xx200)/(0.5))=28.28"s"`

This assumes that he maintains the same acceleration throughout the race.