How do you solve the system a=3b+1 and 5b-2a=1?

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Answer 1 · 2015-12-12T14:41:59

The solution for the system of equations is
#color(blue)(a=-8,b=-3#

#a=color(blue)(3b+1#........equation #(1)#

#5b-2a=1#......equation #(2)#

Solving by substitution

Substituting equation #1# in #2#:

#5b-2a=1#

#5b-2 * (color(blue)(3b+1))=1#

#5b-6b-2=1#

#-b=1+2#

#color(blue)(b=-3#

Finding #a# by substituting the value of #b# in equation #1#:

#a=3b+1#

#a=3 * -3 +1#

#a=-9 +1#

#color(blue)(a=-8#