How do you solve the following linear system: # 3x + y = 1 , x + 2y = -4 #?

1 Answer
Dec 14, 2015

Original Equations:
#3x+y=1#
#x+2y=-4#

First, you isolate a variable. I chose to set the second equation equal to #y#.

#y=-3x+1#

Next, plug the above equation for #y# into the equation you haven't used yet.
#x+2(-3x+1)=-4#

Multiply it out and combine like terms.
#x-6x+2=-4#
#-5x+2=-4#

Now, solve for #x#
#-5x+22=-4#
#-5x=-6#
#x=6/5#

Plug in #x# to solve for #y.# I'm going to plug it into the equation I used first:
#y=-3x+1#
#y=-3(6/5)+1#
#y=-18/5+1#
#y=-13/5#

The answer is #(6/5, -13/5)#