How do you know if #csc x# is an even or odd function?

1 Answer
Dec 21, 2015

Odd.

Explanation:

Know that #sin(-x)=-sin(x)#.

Even function: when #f(-x)=f(x)#
Odd function: when #f(-x)=-f(x)#

In this case, #f(x)=cscx#

#f(x)=1/sinx#

#f(-x)=1/(sin(-x))#

#f(-x)=1/(-sinx)#

#f(-x)=-cscx=-f(x)#

Thus, the function is odd.
graph{csc(x) [-10, 10, -5, 5]}
A property of odd functions is that they have origin symmetry, which means the graph can is symmetrical when reflected over the point #(0,0)#.