What is the standard form of #y(8y + 5)^2 #?

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Answer 1 · 2015-12-21T23:27:14

#16y^3+80y^2+25y#

Completely distribute the expression.

First, square #(8y+5)#.

#y(8y+5)(8y+5)#

#y(16y^2+40y+40y+25)#

#y(16y^2+80y+25)#

#16y^3+80y^2+25y#

This is in standard form—the degrees (exponents) are in descending order.