Question #864f0

1 Answer
Dec 23, 2015

Suppose the number is x. The reminder from 10 gives the last digit of the number. So the number must be #--5#. The reminder from 15 says that the quotient has to be an odd number. Otherwise the number will be divisible by 10. So try the constraint division by 9 to have 4 as reminder.

#15*1+10 = 25#, On division with 9 leads to a reminder of 7.
#15*3+10 = 55#, On division with 9 leads to a reminder of 1.
#15*5+10 = 85#, on division with 9 leads to a reminder of 4.

So this is the required least number.