How do you solve #x^2 + 9x + 18 = 0#?

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Answer 1 · 2015-12-25T00:20:49

#x=-3,-6#

#x^2+9x+18=0#

Find two numbers that when added equal #9# and when multiplied equal #18#. The numbers #3# and #9# meet the criteria.

Rewrite the expression.

#(x+3)(x+6)=0#

Solve for #x#.

#x+3=0#

#x=-3#

#x+6=0#

#x=-6#

#x=-3,-6#