How do you find the derivative of # y = cos(2x)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Bio Dec 27, 2015 #frac{dy}{dx} = -2sin(2x)# Explanation: Use the Chain Rule. Let #u = 2x# #frac{du}{dx} = 2# #frac{dy}{dx} = frac{d}{dx}(cos(2x))# #= frac{d}{dx}(cos(u))# #= frac{d}{du}(cos(u))*frac{du}{dx}# #= (-sin(u))*(2)# #= -2sin(2x)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 1332 views around the world You can reuse this answer Creative Commons License