What are the critical values, if any, of #f(x)= x^3 - 4x^2 + 11 #?

1 Answer
Dec 27, 2015

#c=0,8/3#

Explanation:

The critical values are the #x#-values at which the derivative of the function is equal to zero or does not exist.

Find #f'(x)#.

#f'(x)=3x^2-8x#

Set #f'(x)=0#.

#3x^2-8x=0=>x(3x-8)=0#

#x=0,8/3#

These are two critical values.

Since #f'(x)# is never undefined, there are no critical values there.

Thus, the only two are #0,8/3#.

graph{x^3-4x^2+11 [-17.27, 18.77, -3.52, 14.5]}