A charge of #-2 C# is at #(1,4 )# and a charge of #-1 C# is at #( -2 , 7) #. If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2015-12-29T18:09:37

#10^9"N"#

#P=(1,4)#

#Q=(-2,7)#

Using Pythagoras we can say:

#stackrel(rarr)(PQ)=sqrt((1-(-2)^2+(4-7)^2)#

#stackrel(rarr)(PQ)=sqrt(9+9)#

#stackrel(rarr)(PQ)=sqrt(18)"m"#

#F=k.(q_1xxq_2)/r^2#

#:.F=9xx10^9((-2xx-1))/18#

#F=(cancel(9)xx10^9)/cancel(9)#

#F=10^9"N"#