Question

A projectile is shot at an angle of `pi/6` and a velocity of `2 m/s`. How far away will the projectile land?

Answer 1

The projectile will fall `0.35m` far.

Explanation:

Find the moment when the projectile fall and use the vertical equation `s(y)=vt-1/2at^2=0`; `t(fall)=2v/g=(2*vsin30)/g=0.2s` and subsitute this value in the horizontal equation
`s(t)=vt=(vcos30°)*0.2=0.35m`