How many solutions are there to the system of equations #y + x = 3# and #6 = 2x - y#?

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Answer 1 · 2015-12-30T05:57:09

There is only one solution for the system of equations.
#x=3#
#y=0#

#y+x=3# --------------(1)
#6=2x-y#--------------(2)

Solve equation (1) for #x#

#x=3-y#

Substitute #x=3-y# in equation (2)

#2(3-y)-y=6#
#6-2y-y=6#
#6-3y=6#
#-3y=6-6#
#y=0/(-3)=0#

Put #y=0# in equation (1)

#0+x=3#
#x=3#