Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `24 C` and `-6 C` that are `12 m` apart?

Answer 1

`F=9*10^9N`

Explanation:

The electrostatic force between two charges is given by
`F=(kq_1q_2)/r^2`
Where `F` is the force between the charges, `k` is the constant and its value is `9*10^9`,`q_1` and `q_2` are the magnitudes of the charges and `r` is the distance between the two charges.

Here `F=??`, `k=9*10^9Nm^2/C^2`, `q_1=24C`, `q_2=-6C` and `r=12m`.

`implies F=(9*10^9*24*6)/12^2=(1296*10^9)/144=9*10^9N`
`implies F=9*10^9N`
Note:- The negative sign of the charges is not taken in the problems.