How do you find the remainder when f(x)=x^4+8x^3+12x^2; x+1?

2 Answers

5

Explanation:

Simply perform long division. That is;

(x^4+8x^3 +12x^2+0x+0)/(x+1)

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Dec 31, 2015

The remainder is f(-1) = 5

Explanation:

The remainder of dividing f(x) by a linear factor of the form (x-a) is f(a).

In our case x+1 = x - (-1), so evaluate f(-1) to find the remainder:

f(-1) = (-1)^4+8(-1)^3+12(-1)^2 = 1-8+12 = 5