A charge of #2 C# is at #(5, 2)# and a charge of #-1 C# is at #( 2, -9 )#. If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2015-12-31T16:28:43

#1.4xx10^8"N"#

Using Pythagoras we can get the distance between the charges:

#d=sqrt(3^2+11^2)#

#d=sqrt(130)"m"#

#F=(k.q_1xxq_2)/r^2#

#:.F=9xx10^9.((2xx-1))/(130)#

#=(18xx10^9)/(130)=1.4xx10^(8)"N"#