Question #2f846

2 Answers
Jan 3, 2016

#color(green)("Totally Revised method")#

#color(blue)(x= 535)#

Explanation:

Let the divisor be #x#
Let the first number be #f#
Let the second number be #s#
Let a, b & c be integer values

#color(blue)("Condition 1 with remainder 473")#

#f/x = a+ 473/x# ..............................(1)

#color(blue)("Condition 2 with remainder 298")#

#s/x = b+298/x#...............................(2)

#color(blue)("Condition 3 with remainder 236")#

#(f+s)/x=c+236/x#................................(3) #color(red)("corrected")#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
I think I was initially using a very wrong view point to solve this:

#color(blue)("New method")#

From (1) we know that #x>473#

If we add the remainders from (1) and (2) then we have 771 but the division by #x# reduces this to 236. As in (3)#

From this we can deduce that #473 < x < 771#

As the remainder in (3) is 236 then it has to mean that:

#color(white)(xxxxxxxx)x=771-236 = 535#

May 3, 2017

#535#

Explanation:

When first number is divided by a divisor #x# and remainder is #=473#
#=># divisor #x>473# ...(1)
Similarly for the second number we have #x>298# ......(2)
We observe if (1) is satisfied then (2) gets satisfied automatically as #473>298#

When sum of two numbers is divided by same divisor #x# and we have remainder #236#
it is equivalent to division of sum of two remainders by same divisor #x#
Hence we have the connecting expression
#(473+298)=nx+236# .....(3)
where #n# is an integer and #x# must satisfy equations (1).

For #n=1# we have
#x=(771-236)=535#

For #n=2#
#x=535/2=267.5#
for #n=2,3....#
the obtained values of #x# do not satisfy equation (1)
Hence only valid value is #=535#