What is the standard form of # y=(x - 8) (x + 10) (x - 40) (x + 8) #?

1 Answer
George C.
Jan 3, 2016

#y = x^4-30x^3-464x^2+1920x+25600#

Explanation:

#y = (x-8)(x+10)(x-40)(x+8)#

#=(x-8)(x+8)(x+10)(x-40)#

#=(x^2-64)(x^2-30x-400)#

#=x^2(x^2-30x-400)-64(x^2-30x-400)#

#=x^4-30x^3-400x^2-64x^2+1920x+25600#

#=x^4-30x^3-464x^2+1920x+25600#

Standard form arranges the powers of #x# (or whatever the variable is) in descending order.

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