Question

How do you solve `5^(4x) = 2115`?

Answer 1

Use `loga^b=b*loga`

`x=1.18936`

Explanation:

`5^(4x)=2115`

`log5^(4x)=log2115`

`4x*log5=log2115`

`x=(log2115)/(4*log5)`

`x=1.18936`