How do you rewrite the equation of the circle #(x + 2)^2 + (y + 5)^2 = 9# in general form?

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Answer 1 · 2016-01-05T00:03:50

#(x-(-2))^2+(y-(-5))^2=3^2#

This basically is in the general form of a circle:

#(x-h)^2+(y+k)^2=r^2#

You could, however, make the values of #h,k# and #r# more explicit in the circle equation you provided.

#(x+2)^2+(y+5)^2=9#

The equivalent form of this that better matches the general form of a circle is:

#(x-(-2))^2+(y-(-5))^2=3^2#

Thus, the center is #(-2,-5)# and the radius is #3#.