A projectile is shot from the ground at a velocity of #4 m/s# at an angle of #pi/3#. How long will it take for the projectile to land?

1 Answer
Jan 5, 2016

#0.7"s"#

Explanation:

Use the equation of motion:

#v=u+at#

The vertical component of the initial velocity is #vsintheta#.

At the maximum height the final velocity is zero. We can find the time taken to reach this point.

At this point the equation becomes:

#0=vsintheta-"g"t#

#:.t=(vsintheta)/g#

Converting radians to degrees:

#pi=180^@#

#:.pi/3=180^@/3=60^@#

#:.t=4sin60/9.8=0.35"s"#

The second leg of the flight is when the projectile falls to earth. Because the path is symmetrical this will also be equal to #0.35"s"#.

So total time of flight = #0.35xx2=0.7"s"#