In order to open the clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the shell cracks. If a seagull flies to a height of 27 m, how long will the clam take to fall?
2 Answers
Jan 6, 2016
I found:
Explanation:
The shell will fall with zero initial velocity (dropped) and under the action of acceleration of gravity
We can use:
Jan 6, 2016
Explanation:
Assuming that we are treating the clam as falling vertically from rest with no air resistance, the following should sort it:
Downwards is positive.
We are looking for
Use the constant acceleration equation: