Question

What is the slope of any line perpendicular to the line passing through `(5,-9)` and `(-4,-3)`?

Answer 1

`3/2`

Explanation:

Let the slope of this line be `m` and that of the line perpendicular to it be `m'`, then `m.m' = - 1`

`=>m'= - 1/m = - 1/((y_2 - y_1)/(x_2 - x_1))=-(x_2-x_1)/(y_2-y_1)=- (-4-5)/(-3-(-9))=-(-9)/(-3+9)=-(-9)/6=3/2`
`implies m'=3/2=`.

`implies` the slope of line perpendicular to the line passing through the given points is `3/2`.