Question

A seed company planted a floral mosaic of a national flag. The perimeter of the flag is 420 feet. What is the flag's length and width if the length is 110 feet greater than the width?

Answer 1

Length = 50 feet
Width = 160 feet

Explanation:

I'm assuming the flagpole is not included in this question.
`w=width`
`l = length`

The length compared to the width is:
`w = l + 110` <-- equation 1

The formula for perimeter:
`P = 2w + 2l`
`420 = 2w + 2l` <-- equation 2

Sub the first equation into the second.
`420 = 2(l + 110) + 2l`

Now you can solve for `l` algebraically.
`420 = 2l + 220 + 2l`
`4l = 200`
`l = 50`

Sub the found length into the first equation to find the length.
`w = (50) + 110`
`w = 160`

Therefore the flag is 50 feet long and 160 feet wide.