How do you solve for #x# in the equation #(6x-5)/2 = 2x + 6#?

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Answer 1 · 2016-01-08T03:15:29

#x=7/2#

#(6x-5)/2=2x+6#

Multiply both sides times #2#.

#6x-5=2(2x+6)#

Distribute the #2# on the right side.

#6x-5=4x+12#

Subtract #4x# from both sides.

#6x-4x-5=12#

Simplify.

#2x-5=12#

Add #5# to both sides.

#2x=12-5#

Simplify.

#2x=7#

Divide both sides by #2#.

#x=7/2#