Question

How do you divide `(1+2i)/(2-3i)`?

Answer 1

`frac{7i-4}{13}`

Explanation:

The complex conjugate of `2-3i` is `2+3i`.

`frac{1+2i}{2-3i} = frac{1+2i}{2-3i}*frac{2+3i}{2+3i}`

`= frac{2+6i^2+4i+3i}{2^2-(3i)^2}`

`= frac{7i-4}{13}`