Question

What are the mean and standard deviation of a binomial probability distribution with `n=777` and `p=19/21`?

Answer 1

Mean = 703, Standard Deviation = 8.18 (3sf)

Explanation:

Mean = np = `777*19/21` = 703

Variance = np(1-p) = `777*19/21*2/21` = 66.952...

Standard Deviation = `sqrt(variance)` = 8.18 (3sf)