Question

What is the derivative of `tan^ -1(3x^2)`?

Answer 1

first derivative of `tan^-1 (3x^2)` is

`(6x)/(1+9x^4)`

Explanation:

the formula `d/dx(tan^-1 u)=((du)/dx)/(1+u^2)`

`d/dx(tan^-1(3x^2))=(d/dx(3x^2))/(1+(3x^2)^2`

`d/dx(tan^-1(3x^2))=(6x)/(1+9x^4)`