What is the standard form of #y=(2x+7)(-3x-2) -4x^2-8#?

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Answer 1 · 2016-01-10T19:01:06

#y=-10x^2-25x-22#

Distribute the binomials using the FOIL method.

#y=overbrace(2x(-3x))^"First"+overbrace(2x(-2))^"Outside"+overbrace(7(-3x))^"Inside"+overbrace(7(-2))^"Last"-4x^2-8#

#y=-6x^2-4x-21x-14-4x^2-8#

Sort by term (#x# with #x#, constants with constants):

#y=-6x^2-4x^2-4x-21x-14-8#

Combine like terms.

#y=-10x^2-25x-22#

This is in standard form since the exponents are in descending order.