Question

How do you solve the following system: #4x+3y= -1 , 4x-2y=4 #?

Answer 1

`y=-1`
`x = 1/2`

Explanation:

Noting that the coefficient of `x` is the same in both equations, we can get an expression just in `y` buy subtracting the second equation from the first.
`4x+3y = -1`
`-(4x -2y = 4)`
`5y = -5`
`y=-1`
Substituting into either of the equations(I choose the second one) we can evaluate `x`
`4x = 4+2*(-1)`
`4x = 2`
`x = 1/2`