What is the antiderivative of #(ln x)^2#? Calculus Techniques of Integration Integration by Parts 1 Answer Leland Adriano Alejandro Jan 13, 2016 #x(ln x)^2 - 2x ln x + 2x +C# Explanation: Let #u=(ln x)^2# #dv = dx# #v=x# #du = 2(ln x)* dx/x# Answer link Related questions How do I find the integral #int(x*ln(x))dx# ? How do I find the integral #int(cos(x)/e^x)dx# ? How do I find the integral #int(x*cos(5x))dx# ? How do I find the integral #int(x*e^-x)dx# ? How do I find the integral #int(x^2*sin(pix))dx# ? How do I find the integral #intln(2x+1)dx# ? How do I find the integral #intsin^-1(x)dx# ? How do I find the integral #intarctan(4x)dx# ? How do I find the integral #intx^5*ln(x)dx# ? How do I find the integral #intx*2^xdx# ? See all questions in Integration by Parts Impact of this question 1208 views around the world You can reuse this answer Creative Commons License