How do you find the remainder when #P(x) = x^4 - 9x^3 - 5x^2 - 3x+4# is divided by x+3?
1 Answer
Jan 13, 2016
292
Explanation:
To divide by (x + 3 ) you don't have to divide by (x + 3 ) . Using the
Remainder Theorem you just have to evaluate P( - 3 ).
# P(- 3 ) = ( - 3 )^4 -9(- 3 )^3 - 5(- 3 )^2 - 3( - 3 ) + 4 # = 81 + 243 - 45 + 9 + 4
= 292
ie. remainder = 292
