Question

Question #e951f

Answer 1

`10^6` fluorine molecules have a mass of `(10^6cancel("molecules"))/(6.022xx10^23*cancel("molecules")*cancel(mol^-1)) xx 38*g*cancel(mol^-1)` `=` `??g`

Explanation:

Of course fluorine exists as the gaseous `F_2` molecule at normal temperatures and pressures. A million fluorine molecules will not have a very large mass.

I used Avogadro's number in the calculation above, because I know that Avogadro's number (i.e. a MOLE) of fluorine ATOMS (i.e. `6.022xx10^23` fluorine atoms) has a mass of `19.00` `g` precisely. What is the mass of Avogadro's number of fluorine molecules?