How do you simplify #(9 – 6i) – (12 + 2i)#?
1 Answer
Jan 14, 2016
simplification is - 3 - 8i
Explanation:
To add or subtract complex numbers , add/subtract the real parts and add/subtract the coefficients of the imaginary parts.
for ( a + bi ) + (c + di ) = ( a + c ) + (b + d ) i
in this question (9 - 6i ) - (12 + 2i ) = (9 - 12 ) +( - 6 - 2 )i = - 3 - 8i