Question

How do you differentiate `g(x) =sin(3-2x) cos(5x)` using the product rule?

Answer 1

`g' (x)=-2* cos(3-2x) *cos 5x -5 sin(3-2x) *sin 5x`

Explanation:

from the given
`g(x) = sin (3-2x) cos 5x`

Let `u=sin (3-2x)` and let `v= cos 5x`

use the formula

`d/dx(uv) = u (dv)/dx+ v (du)/dx`