How many moles are present in #2.1 * 10^24# atoms of calcium?

1 Answer
anor277
Jan 21, 2016

There are #6.022140857(74)xx10^(23)# #"calcium"# #"atoms"# in 1 mole of #Ca#.

Explanation:

You have specified #2.1xx10^24# calcium atoms.

So #(2.1xx10^24*"calcium atoms")/(6.022xx10^(23)*"calcium atoms mol"^-1)# #=# #??# #mol#

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