Question

What is the equation of the line that goes through `(3, -5)` and is parallel to `y = -10/3x + 3`?

Answer 1

`y = -10/3*x +5`

Explanation:

The required line is parallel to `y = -10/3*x +3` and therefore has the same slope of `-10/3`

Using the generic equation for a line `y=mx+c` and the given point `(3,-5)` we can say
`-5 = (-10/3)*(3) +c`
`-5+10 = c`

`c = 5`

Therefore the required equation is
`y = -10/3*x +5`