Question

What are the three consecutive integers whose sum is 126?

Answer 1

The numbers are `41`, `42`, and `43`

Explanation:

Let `x` be the first number

Let `x+1` be the second number

Let `x+2` be the third number

We are given that the sum of the numbers is 126 so we can write

`x+(x+1)+(x+2)=126`

`x+x+1+x+2=126`

Combine like terms

`3x+3=126`

Subtract `3` from both sides

`3x=123`

Divide both sides by `3`

`x=41`

So `x+1=42` and `x+2=43`