What are the three consecutive integers whose sum is 126?

1 Answer
Jan 23, 2016

The numbers are 41, 42, and 43

Explanation:

Let x be the first number

Let x+1 be the second number

Let x+2 be the third number

We are given that the sum of the numbers is 126 so we can write

x+(x+1)+(x+2)=126

x+x+1+x+2=126

Combine like terms

3x+3=126

Subtract 3 from both sides

3x=123

Divide both sides by 3

x=41

So x+1=42 and x+2=43