A projectile is shot at an angle of #pi/12 # and a velocity of #3 6 m/s#. How far away will the projectile land?

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Answer 1 · 2016-01-24T17:09:09

Data:-

Angle of throwing#=theta=pi/12#

Initial Velocit#+# Muzzle Velocity#=v_0=36m/s#

Acceleration due to gravity#=g=9.8m/s^2#

Range#=R=??#

Sol:-

We know that:

#R=(v_0^2sin2theta)/g#

#implies R=(36^2sin(2*pi/12))/9.8=(1296sin(pi/6))/9.8=(1296*0.5)/9.8=648/9.8=66.1224 m#

#implies R=66.1224 m#