Question #253eb

Question

720 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-25T02:33:32

Use the following variables ...

T = sum of the thrown out scores
N = sum of the not thrown out scores

#(T+N)/10=70#

#N/6=75#

#N=75xx6=450#

Now substitute back into the first equation and solve for T ...

#(T+N)/10=70#

#(T+450)/10=70#

#T+450=70xx10=700#

#T=700-450=250#

Finally, we can find the average of the 4 thrown out scores ...

average #=T/4=250/4=62.5#

hope that helped