Question

How do you solve `2^(x+2) = 8`?

Answer 1

`x=1`

Explanation:

Given equation is `2^(x+2)=8`

I'm sure you're familiar with the law of exponents and that `a^(m+n)=a^m*a^n`

So, in the main equation, we get `2^(x+2)=2^x2^2=4*2^x`
So, `cancel{4}^1*2^x=cancel{8}^2`
So, `2^x=2`

I'm sure it's obvious from here.