How do you solve 2^(x+2) = 8?

1 Answer
Jan 26, 2016

x=1

Explanation:

Given equation is 2^(x+2)=8

I'm sure you're familiar with the law of exponents and that a^(m+n)=a^m*a^n

So, in the main equation, we get 2^(x+2)=2^x2^2=4*2^x
So, cancel{4}^1*2^x=cancel{8}^2
So, 2^x=2

I'm sure it's obvious from here.