How do you write an equation in standard form given (-3, -3), (7,2)?

1 Answer
Jan 27, 2016

#x-2y=3#

Explanation:

Just so we know what our target is:
Standard form for a linear equation is
#color(white)("XXX")Ax+By=C#

Step 1: write the equation in slope-point form

slope: #m=(Delta y)/(Delta x) = (2-(-3))/(7-(-3)) = 5/10 = 1/2#

slope point form with slope #m# through a point #(barx,bary)# is
#color(white)("XXX")(y-bary) = m(x-barx)#
Using the above slope and #(-3,-3)# for #(barx,bary)#
#color(white)("XXX")y+3 = 1/2(x+3)#

Step 2: convert from slope-point to standard form

#y+3=1/2(x+3)#

#rarr 2y+6 = x+3#

#rarr x-2y=3##color(white)("XXX")#or if you want to be picky: #1x+(-2)y=3#