What is the integral of $\int f (x) = e^{3 x}$ $int f(x)=e^(3x)$ from 0 to 2?

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What is the integral of $\int f (x) = e^{3 x}$ $int f(x)=e^(3x)$ from 0 to 2?

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Answer 1 · 2016-01-28T08:04:12

$\frac{e^{6} - 1}{3}$ $(e^6-1)/3$

Explanation:

$\int_{0}^{2} f (x)$ $int_0^2f(x)$
$= \int_{0}^{2} e^{3 x}$ $=int_0^2 e^(3x)$
$= {[\frac{e^{3 x}}{3}]}_{0}^{2}$ $=[(e^(3x))/3]_0^2$
$= [(\frac{e^{3 \cdot 2}}{3}) - (\frac{e^{3 \cdot 0}}{3})]$ $=[(e^(3*2)/3)-(e^(3*0)/3)]$
$= \frac{e^{6} - 1}{3}$ $=(e^6-1)/3$

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What is the integral of $\int f (x) = e^{3 x}$ $int f(x)=e^(3x)$ from 0 to 2?

1 Answer

Explanation:

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