What is the antiderivative of #(ln^6 x)/x#?
1 Answer
Jan 31, 2016
Explanation:
Use substitution.
Let
Finding the antiderivative is equivalent to finding
#int(ln^6x)/xdx#
This can be rewritten as
#=intln^6x(1/x)dx#
Using the substitutions previously defined
#=intu^6du#
This is equal to
#=1/7u^7+C#
Resubstitute
#=(ln^7x)/7+C#