How do you write #(x^3 - x^2 - 6x)# in factored form?

1 Answer
Feb 1, 2016

#x(x^2-x-6)#
#x(x-3)(x+2)#

Explanation:

#x^3-x^2-6x#

1) Simplify the polynomial.
( What does each term have in common? )

In this case, they each have #1x# or #x# in common

2) Place the extraneous parts on the outside.
(Put what you just simplified outside the parentheses)

In this example, that means #x#
#x(x^2-x-6)#

3) Factor the trinomial.
(Just like you usually would)

I was taught to think of a number that multiplies to make the last number (#6#) and add together to make the middle coefficient (#1#). When you do that you get #-3# and #2#. So, the answer is:
#x(x-3)(x+2)#

Notes:
- You should always simplify before you begin factoring because it makes it easier and faster.
- You can always check you answer by multiplying the equation back out again. If you did it right, you should get what you started with