Question

A projectile is shot at an angle of `pi/3` and a velocity of `72 m/s`. How far away will the projectile land?

Answer 1

The distance is `457.64m`

Explanation:

We know that the distance is given by

`R=(v^2sin2theta)/g`

`=(72^2sin(2*pi/3))/9.81`

`=457.64m`