Question

A charge of `24 C` passes through a circuit every `4 s`. If the circuit can generate `45 W` of power, what is the circuit's resistance?

Answer 1

`1.25 Omega`

Explanation:

The power `P = I^2R` where `I` is the current and `R` is the resistance. Therefore the resistance `R=P/I^2`

`I= 24/4 = 6Amps`

`R= 45/6^2 = 45/36 = 5/4 = 1.25 Omega`